What is x-1/2 (x+3)<= 2x-x(3/2-3/x) ?

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x-1/2 (x+3)<= 2x-x(3/2-3/x)

x - \frac{1}{2} (x + 3) \leq 2 x - x (\frac{3}{2} - \frac{3}{x})

x < 0 or x > 0

Interval Notation

(- \infty, 0) \cup (0, \infty)

Solution steps

x - \frac{1}{2} (x + 3) \leq 2 x - x (\frac{3}{2} - \frac{3}{x})

Rewrite in standard form

- \frac{3}{2} - 3 \leq 0

True for all x

Combine the intervals

True for all x and x < 0 or x > 0

Merge Overlapping Intervals

x < 0 or x > 0

y^{2} - 6 y + 1 = 0

\frac{6 - ( - 8 )}{4 - ( - 3 )}

2 = \frac{c}{( 2 \cdot 0.1 \cdot ( \frac{π ^{2}}{10} ) )}

172 8^{\frac{1}{3}}

10 = - 4 x + 3 x^{2}

What is x-1/2 (x+3)<= 2x-x(3/2-3/x) ?
The solution to x-1/2 (x+3)<= 2x-x(3/2-3/x) is x<0\lor x>0