What is expand x^xln(x)(ln(x)+1)+x^{x-1} ?

The solution to expand x^xln(x)(ln(x)+1)+x^{x-1} is x^xln^2(x)+x^xln(x)+x^{x-1}

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expand x^xln(x)(ln(x)+1)+x^{x-1}

expand

x^{x} ln (x) (ln (x) + 1) + x^{x - 1}

x^{x} ln^{2} (x) + x^{x} ln (x) + x^{x - 1}

Solution steps

x^{x} ln (x) (ln (x) + 1) + x^{x - 1}

Expand

x^{x} ln (x) (ln (x) + 1) : x^{x} ln^{2} (x) + x^{x} ln (x)

= x^{x} ln^{2} (x) + x^{x} ln (x) + x^{x - 1}

8 cos (2 (x + 1))

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π (3 x + 2)^{2}

What is expand x^xln(x)(ln(x)+1)+x^{x-1} ?
The solution to expand x^xln(x)(ln(x)+1)+x^{x-1} is x^xln^2(x)+x^xln(x)+x^{x-1}