What is the derivative of (z(1/z+1)) ?

The derivative of (z(1/z+1)) is 1

What is the first derivative of (z(1/z+1)) ?

The first derivative of (z(1/z+1)) is 1

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\frac{d}{d x} ((x) (\frac{1}{x} + 1))

1

Solution steps

\frac{d}{d x} ((x) (\frac{1}{x} + 1))

Simplify

(x) (\frac{1}{x} + 1) : 1 + x

= \frac{d}{d x} (1 + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d x}{d x}

\frac{d}{d x} (1) = 0

\frac{d x}{d x} = 1

= 0 + 1

Simplify

= 1

Z (sin (2) (x) + 2) d x

co a (\frac{π}{3} - x) - 1

\frac{w ( l - x ) ^{2}}{2}

(- \frac{3}{4} x + y = - 1) (- 4)

, 5 ((3 + 2 i) + (3 + 2 i) (1 + 5 i))

What is the derivative of (z(1/z+1)) ?
The derivative of (z(1/z+1)) is 1
What is the first derivative of (z(1/z+1)) ?
The first derivative of (z(1/z+1)) is 1