What is expand (dx)/d (y^2+x^2=13) ?

The solution to expand (dx)/d (y^2+x^2=13) is (y^2dx)/d+(x^2dx)/d =13

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expand (dx)/d (y^2+x^2=13)

expand

\frac{d x}{d} (y^{2} + x^{2} = 13)

\frac{y ^{2} d x}{d} + \frac{x ^{2} d x}{d} = 13

Solution steps

\frac{d x}{d} (y^{2} + x^{2} = 13)

= \frac{d x}{d} (y^{2} + 13 = x^{2})

Apply the distributive law:

a (b + c) = ab + a c

a = \frac{d x}{d}, b = y^{2}, c = x^{2} = 13

\frac{d x}{d} y^{2} + \frac{d x}{d} x^{2} = 13

Expand

\frac{d x}{d} y^{2} + \frac{d x}{d} x^{2} : \frac{y ^{2} d x}{d} + \frac{x ^{2} d x}{d}

\frac{y ^{2} d x}{d} + \frac{x ^{2} d x}{d} = 13

\frac{d}{d t} ((θ) (5 + 2 sin (3 θ)))

6 (4 ln (2) - 1)

\frac{2 ( x + 2 )}{x + 3}

e^{5 x} (2 x - 1)

- 5 (2 e - 3 d + 1 = 91)

What is expand (dx)/d (y^2+x^2=13) ?
The solution to expand (dx)/d (y^2+x^2=13) is (y^2dx)/d+(x^2dx)/d =13