What is expand 4e^x(1+ln(x))(sin(x)) ?

The solution to expand 4e^x(1+ln(x))(sin(x)) is 4e^xsin(x)+4e^xsin(x)ln(x)

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expand 4e^x(1+ln(x))(sin(x))

expand

4 e^{x} (1 + ln (x)) (sin (x))

4 e^{x} sin (x) + 4 e^{x} sin (x) ln (x)

Solution steps

4 e^{x} (1 + ln (x)) (sin (x))

= 4 e^{x} (sin (x)) (1 + ln (x))

Apply the distributive law:

a (b + c) = ab + a c

a = 4 e^{x} (sin (x)), b = 1, c = ln (x)

= 4 e^{x} (sin (x)) \cdot 1 + 4 e^{x} (sin (x)) ln (x)

= 4 \cdot 1 \cdot e^{x} (sin (x)) + 4 e^{x} (sin (x)) ln (x)

Simplify

4 \cdot 1 \cdot e^{x} (sin (x)) + 4 e^{x} (sin (x)) ln (x) : 4 e^{x} sin (x) + 4 e^{x} sin (x) ln (x)

= 4 e^{x} sin (x) + 4 e^{x} sin (x) ln (x)

\frac{- r - 5}{( r + 1 ) ( r - 1 )}

\frac{x ^{3}}{( x - 1 ) ( x + 3 )}

\frac{( 8 + x ) ^{3}}{8}

(x^{2} + 1) (3 x - 1) (2 x - 3) d x

(9 + 1 = - 5) \cdot (9 - 1 - 5)

What is expand 4e^x(1+ln(x))(sin(x)) ?
The solution to expand 4e^x(1+ln(x))(sin(x)) is 4e^xsin(x)+4e^xsin(x)ln(x)