What is expand ((8+x)^3)/8 ?

The solution to expand ((8+x)^3)/8 is (x^3)/8+3x^2+24x+64

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expand ((8+x)^3)/8

expand

\frac{( 8 + x ) ^{3}}{8}

\frac{x ^{3}}{8} + 3 x^{2} + 24 x + 64

Solution steps

\frac{( 8 + x ) ^{3}}{8}

(8 + x)^{3} = 512 + 192 x + 24 x^{2} + x^{3}

= \frac{512 + 192 x + 24 x ^{2} + x ^{3}}{8}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{512 + 192 x + 24 x ^{2} + x ^{3}}{8} = \frac{512}{8} + \frac{192 x}{8} + \frac{24 x ^{2}}{8} + \frac{x ^{3}}{8}

= \frac{512}{8} + \frac{192 x}{8} + \frac{24 x ^{2}}{8} + \frac{x ^{3}}{8}

Divide the numbers:

\frac{512}{8} = 64

= 64 + \frac{192 x}{8} + \frac{24 x ^{2}}{8} + \frac{x ^{3}}{8}

Divide the numbers:

\frac{192}{8} = 24

= 64 + 24 x + \frac{24 x ^{2}}{8} + \frac{x ^{3}}{8}

Divide the numbers:

\frac{24}{8} = 3

= 64 + 24 x + 3 x^{2} + \frac{x ^{3}}{8}

Rewrite in standard form

= \frac{x ^{3}}{8} + 3 x^{2} + 24 x + 64

(x^{2} + 1) (3 x - 1) (2 x - 3) d x

(9 + 1 = - 5) \cdot (9 - 1 - 5)

\frac{2 n + 1}{( n ) ( n + 1 )}

v (0, 0) f (0, - \frac{1}{39})

1 \circ (3 x + 1)

What is expand ((8+x)^3)/8 ?
The solution to expand ((8+x)^3)/8 is (x^3)/8+3x^2+24x+64