What is expand v(0,0)f(0,-1/39) ?

The solution to expand v(0,0)f(0,-1/39) is 0*(0*0,)vf,-1/39 (0*0,)vf

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expand v(0,0)f(0,-1/39)

expand

v (0, 0) f (0, - \frac{1}{39})

0 \cdot (0 \cdot 0,) v f, - \frac{1}{39} (0 \cdot 0,) v f

Solution steps

v (0, 0) f (0, - \frac{1}{39})

= (0 \cdot 0,) (0, - \frac{1}{39}) v f

Apply the distributive law:

a (b - c) = ab - a c

a = v (0, 0) f, b = 0,, c = \frac{1}{39}

= v (0, 0) f \cdot 0, - v (0, 0) f \frac{1}{39}

= 0 \cdot (0 \cdot 0,) v f, - \frac{1}{39} (0 \cdot 0,) v f

1 \circ (3 x + 1)

\frac{( x + 8 y ) ( x + 3 y )}{( x + y )}

\frac{( v - 1 ) ^{3}}{v ^{2}}

(x - 1) (\cdot + 2)

x^{2} 6^{x} - 64 (6^{x})

What is expand v(0,0)f(0,-1/39) ?
The solution to expand v(0,0)f(0,-1/39) is 0*(0*0,)vf,-1/39 (0*0,)vf