What is expand (((x-1)^3))/(x+1) ?

The solution to expand (((x-1)^3))/(x+1) is (x^3-3x^2+3x-1)/(x+1)

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expand (((x-1)^3))/(x+1)

expand

\frac{( ( x - 1 ) ^{3} )}{x + 1}

\frac{x ^{3} - 3 x ^{2} + 3 x - 1}{x + 1}

Solution steps

\frac{( x - 1 ) ^{3}}{x + 1}

(x - 1)^{3} = x^{3} - 3 x^{2} + 3 x - 1

= \frac{x ^{3} - 3 x ^{2} + 3 x - 1}{x + 1}

\frac{( 3 x - 1 ) ( x + 1 )}{2 ( x - 1 )}

e x p an (3 z^{2} - 2) (z^{2} - 3 z - 4)

\frac{π ( 144 ln ( 6 ) + 1295 )}{144}

9 (x + 3 = 27)

R (w^{2} L C - w L \cdot 2 π)

What is expand (((x-1)^3))/(x+1) ?
The solution to expand (((x-1)^3))/(x+1) is (x^3-3x^2+3x-1)/(x+1)