What is expand-((x+7)(x-4))/(18) ?

The solution to expand-((x+7)(x-4))/(18) is -(x^2)/(18)-x/6+14/9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand-((x+7)(x-4))/(18)

expand

- \frac{( x + 7 ) ( x - 4 )}{18}

- \frac{x ^{2}}{18} - \frac{x}{6} + \frac{14}{9}

Solution steps

- \frac{( x + 7 ) ( x - 4 )}{18}

Expand

(x + 7) (x - 4) : x^{2} + 3 x - 28

= - \frac{x ^{2} + 3 x - 28}{18}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{2} + 3 x - 28}{18} = - (\frac{x ^{2}}{18}) - (\frac{3 x}{18}) - (- \frac{28}{18})

= - (\frac{x ^{2}}{18}) - (\frac{3 x}{18}) - (- \frac{28}{18})

Remove parentheses:

(a) = a, - (- a) = a

= - \frac{x ^{2}}{18} - \frac{3 x}{18} + \frac{28}{18}

Cancel

\frac{3 x}{18} : \frac{x}{6}

= - \frac{x ^{2}}{18} - \frac{x}{6} + \frac{28}{18}

Cancel

\frac{28}{18} : \frac{14}{9}

= - \frac{x ^{2}}{18} - \frac{x}{6} + \frac{14}{9}

\frac{( x + 1 ) ^{2}}{3 x ^{4}}

\frac{63}{( x + 8 ) x}

\frac{4 x}{( - x + 1 ) ( x + 1 )}

\frac{3 x - 5}{( x - 3 ) ( x ^{2} - 3 x + 2 )}

(- 3, 4, 2) (2 x - 4 y + z - 7)

What is expand-((x+7)(x-4))/(18) ?
The solution to expand-((x+7)(x-4))/(18) is -(x^2)/(18)-x/6+14/9