What is expand ((x)= 3/2 x+1)(-3) ?

The solution to expand ((x)= 3/2 x+1)(-3) is -3x=(3x)/2-3

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expand ((x)= 3/2 x+1)(-3)

expand

((x) = \frac{3}{2} x + 1) (- 3)

- 3 x = \frac{3 x}{2} - 3

Solution steps

((x) = \frac{3}{2} x + 1) (- 3)

= (- 3) (\frac{3}{2} = (x) x + 1)

Apply the distributive law:

a (b + c) = ab + a c

a = (- 3), b = (x) = \frac{3}{2} x, c = 1

(- 3) (x) = \frac{3}{2} x + (- 3) \cdot 1

Simplify

(- 3) (x) = \frac{3}{2} x + (- 3) \cdot 1 : - 3 x = \frac{3 x}{2} - 3

- 3 x = \frac{3 x}{2} - 3

\frac{d y}{y ( 1 + 3 y + 2 y ^{3} )}

\frac{2 x + 2 ( 3 + a ) ^{2}}{y - 1}

d y (2 a x + b) d x

- (- 5)^{2}

4 (x - 8 = 40)

What is expand ((x)= 3/2 x+1)(-3) ?
The solution to expand ((x)= 3/2 x+1)(-3) is -3x=(3x)/2-3