What is expand ((n+1)u)/(1-(n+1)u) ?

The solution to expand ((n+1)u)/(1-(n+1)u) is (nu+u)/(1-nu-u)

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expand ((n+1)u)/(1-(n+1)u)

expand

\frac{( n + 1 ) u}{1 - ( n + 1 ) u}

\frac{n u + u}{1 - n u - u}

Solution steps

\frac{( n + 1 ) u}{1 - ( n + 1 ) u}

Expand

1 - (n + 1) u : 1 - n u - u

= \frac{u ( n + 1 )}{1 - n u - u}

Expand

(n + 1) u : n u + u

= \frac{n u + u}{1 - n u - u}

\frac{( b - a ) ^{2}}{n}

\frac{s + 6}{( s ^{2} + s + c ) ( s + 4 )}

(y^{2} - 4 y + 9) - (3 y^{2} - 6 y = 9)

\frac{- 3 ( x + h ) ^{2} + 3 ( x + h ) - 4}{h}

\frac{k ^{a}}{n ( k ^{a} - n ^{a} )}

What is expand ((n+1)u)/(1-(n+1)u) ?
The solution to expand ((n+1)u)/(1-(n+1)u) is (nu+u)/(1-nu-u)