What is expand ((x-2)(x-4))/(15) ?

The solution to expand ((x-2)(x-4))/(15) is (x^2}{15}-\frac{2x)/5+8/15

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expand ((x-2)(x-4))/(15)

expand

\frac{( x - 2 ) ( x - 4 )}{15}

\frac{x ^{2}}{15} - \frac{2 x}{5} + \frac{8}{15}

Solution steps

\frac{( x - 2 ) ( x - 4 )}{15}

Expand

(x - 2) (x - 4) : x^{2} - 6 x + 8

= \frac{x ^{2} - 6 x + 8}{15}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{2} - 6 x + 8}{15} = \frac{x ^{2}}{15} - \frac{6 x}{15} + \frac{8}{15}

= \frac{x ^{2}}{15} - \frac{6 x}{15} + \frac{8}{15}

Cancel

\frac{6 x}{15} : \frac{2 x}{5}

= \frac{x ^{2}}{15} - \frac{2 x}{5} + \frac{8}{15}

\frac{3 \cdot ( 5 + x )}{2}

y lo g_{10} (x y) (1 + ln (x y))

x + x + x + 2

(e^{x} + e^{- 2 x})^{2}

- 6 (2 w - 3 + 6 w = 6 + 2 (6 w - 1))

What is expand ((x-2)(x-4))/(15) ?
The solution to expand ((x-2)(x-4))/(15) is (x^2}{15}-\frac{2x)/5+8/15