What is expand (x^2+3x)cos(x)dx ?

The solution to expand (x^2+3x)cos(x)dx is x^2cos(x)dx+3xcos(x)dx

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expand (x^2+3x)cos(x)dx

expand

(x^{2} + 3 x) cos (x) d x

x^{2} cos (x) d x + 3 x cos (x) d x

Solution steps

(x^{2} + 3 x) cos (x) d x

= cos (x) (x^{2} + 3 x) d x

Apply the distributive law:

a (b + c) = ab + a c

a = cos (x) d x, b = x^{2}, c = 3 x

= cos (x) d x x^{2} + cos (x) d x \cdot 3 x

= x^{2} cos (x) d x + 3 x cos (x) d x

10 + (1 - 2) i

\frac{( x - 9 )}{( - 8 x + 2 ) ( 5 x + 4 )}

\frac{2 ( 3 x - 4 )}{3 x ^{2} - 8 x + 6}

(t - 3) (s^{2} + 4)^{^{'}}

(e + 12)^{2}

What is expand (x^2+3x)cos(x)dx ?
The solution to expand (x^2+3x)cos(x)dx is x^2cos(x)dx+3xcos(x)dx