What is expand ((-2c+1)(2c+1))/4 ?

The solution to expand ((-2c+1)(2c+1))/4 is 1/4-c^2

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expand ((-2c+1)(2c+1))/4

expand

\frac{( - 2 c + 1 ) ( 2 c + 1 )}{4}

\frac{1}{4} - c^{2}

Solution steps

\frac{( - 2 c + 1 ) ( 2 c + 1 )}{4}

Expand

(- 2 c + 1) (2 c + 1) : 1 - 4 c^{2}

= \frac{1 - 4 c ^{2}}{4}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{1 - 4 c ^{2}}{4} = \frac{1}{4} - \frac{4 c ^{2}}{4}

= \frac{1}{4} - \frac{4 c ^{2}}{4}

Divide the numbers:

\frac{4}{4} = 1

= \frac{1}{4} - c^{2}

\frac{2 x - 1}{x ^{2} ( x + 1 ) ^{3}}

3 c + 6

(x - 3) (x = + 2)

7 (7 a - 14 = 7 (8 a + 2))

y (- 1 - y^{2} + C = (x + C))

What is expand ((-2c+1)(2c+1))/4 ?
The solution to expand ((-2c+1)(2c+1))/4 is 1/4-c^2