What is expand y(-sqrt(1-y^2)+C=(x+C)) ?

The solution to expand y(-sqrt(1-y^2)+C=(x+C)) is -ysqrt(1-y^2)+Cy=x+C

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expand y(-sqrt(1-y^2)+C=(x+C))

expand

y (- 1 - y^{2} + C = (x + C))

- y 1 - y^{2} + C y = x + C

Solution steps

y (- 1 - y^{2} + C = (x + C))

= y (- 1 - y^{2} + = C (x + C))

Apply the distributive law:

a (b + c) = ab + a c

a = y, b = - 1 - y^{2}, c = C = (x + C)

y (- 1 - y^{2}) + y C = (x + C)

Apply minus-plus rules

+ (- a) = - a

- y 1 - y^{2} + C y = (x + C)

Expand

(x + C) : x + C

- y 1 - y^{2} + C y = x + C

(3 x + 2) (7 x - 1)^{'}

2 - 1

sin (2 (t + 2 π))

f (4 + Δ^{4})

1001 \cdot 34

What is expand y(-sqrt(1-y^2)+C=(x+C)) ?
The solution to expand y(-sqrt(1-y^2)+C=(x+C)) is -ysqrt(1-y^2)+Cy=x+C