What is expand 1/(P(0.0394-0.0002P)) ?

The solution to expand 1/(P(0.0394-0.0002P)) is 1/(0.0394P-0.0002P^2)

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expand 1/(P(0.0394-0.0002P))

expand

\frac{1}{P ( 0.0394 - 0.0002 P )}

\frac{1}{0.0394 P - 0.0002 P ^{2}}

Solution steps

\frac{1}{P ( 0.0394 - 0.0002 P )}

Expand

P (0.0394 - 0.0002 P) : 0.0394 P - 0.0002 P^{2}

= \frac{1}{0.0394 P - 0.0002 P ^{2}}

(3 x + 1) \cdot 3 e^{3 x}

8 (t + 1) y^{'} (t) - 6 y - 12 t

d x (3 x^{y} ln (x) + e^{y} y ln (x))

- lo g_{b} (w)

(3 x + 2 y = 7, 8) (3 x + 2 y = 92)

What is expand 1/(P(0.0394-0.0002P)) ?
The solution to expand 1/(P(0.0394-0.0002P)) is 1/(0.0394P-0.0002P^2)