What is expand dx(3x^yln(x)+e^yyln(x)) ?

The solution to expand dx(3x^yln(x)+e^yyln(x)) is 3x^yln(x)dx+e^yyln(x)dx

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expand dx(3x^yln(x)+e^yyln(x))

expand

d x (3 x^{y} ln (x) + e^{y} y ln (x))

3 x^{y} ln (x) d x + e^{y} y ln (x) d x

Solution steps

d x (3 x^{y} ln (x) + e^{y} y ln (x))

Apply the distributive law:

a (b + c) = ab + a c

a = d x, b = 3 x^{y} ln (x), c = e^{y} y ln (x)

= d x \cdot 3 x^{y} ln (x) + d x e^{y} y ln (x)

= 3 x^{y} ln (x) d x + e^{y} y ln (x) d x

- lo g_{b} (w)

(3 x + 2 y = 7, 8) (3 x + 2 y = 92)

[\frac{4 s}{( x ^{2} + 4 ) ( 6 s + 3 )}]

u^{1} (u^{2} v^{3}, - u^{3} v^{2})

2 (x + 2 = 6)

What is expand dx(3x^yln(x)+e^yyln(x)) ?
The solution to expand dx(3x^yln(x)+e^yyln(x)) is 3x^yln(x)dx+e^yyln(x)dx