What is expand 7(x+Δx)^2-5(x+Δx) ?

The solution to expand 7(x+Δx)^2-5(x+Δx) is 7x^2+14Δx^2+7Δ^2x^2-5x-5Δx

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expand 7(x+Δx)^2-5(x+Δx)

expand

7 (x + Δ x)^{2} - 5 (x + Δ x)

7 x^{2} + 14Δ x^{2} + 7 Δ^{2} x^{2} - 5 x - 5Δ x

Solution steps

7 (x + Δ x)^{2} - 5 (x + Δ x)

Expand

- 5 (x + Δ x) : - 5 x - 5Δ x

= 7 (x + Δ x)^{2} - 5 x - 5Δ x

Simplify

7 (x + Δ x)^{2} - 5 x - 5Δ x : 7 x^{2} + 14Δ x^{2} + 7 Δ^{2} x^{2} - 5 x - 5Δ x

= 7 x^{2} + 14Δ x^{2} + 7 Δ^{2} x^{2} - 5 x - 5Δ x

\frac{( a + h ) ^{3}}{( a + h ) ^{2} + 1}

\frac{k ( s + 2 )}{s ^{2} - s + k s + 2 k}

\frac{( 3 x + 10 ) ( x - 6 )}{6}

\frac{5 ( s + 2 )}{s ( s ^{2} + 8 s + 15 )}

\frac{8 - ( - 1 ) ^{x}}{x}

What is expand 7(x+Δx)^2-5(x+Δx) ?
The solution to expand 7(x+Δx)^2-5(x+Δx) is 7x^2+14Δx^2+7Δ^2x^2-5x-5Δx