What is expand (n(n+1)(n-1))/3 ?

The solution to expand (n(n+1)(n-1))/3 is (n^3)/3-n/3

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expand (n(n+1)(n-1))/3

expand

\frac{n ( n + 1 ) ( n - 1 )}{3}

\frac{n ^{3}}{3} - \frac{n}{3}

Solution steps

\frac{n ( n + 1 ) ( n - 1 )}{3}

Expand

n (n + 1) (n - 1) : n^{3} - n

= \frac{n ^{3} - n}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{n ^{3} - n}{3} = \frac{n ^{3}}{3} - \frac{n}{3}

= \frac{n ^{3}}{3} - \frac{n}{3}

A (3, - 2, 1)

\frac{a}{s ( 1 + T s )}

\frac{x + 4}{( x - 1 ) ^{2}}

(\frac{1 - 4 y}{3})^{2}

\frac{3 ( x + h ) ^{2} - 3 x}{h}

What is expand (n(n+1)(n-1))/3 ?
The solution to expand (n(n+1)(n-1))/3 is (n^3)/3-n/3