What is expand ((21x-9)(15x+3))/7 ?

The solution to expand ((21x-9)(15x+3))/7 is 45x^2-(72x)/7-27/7

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expand ((21x-9)(15x+3))/7

expand

\frac{( 21 x - 9 ) ( 15 x + 3 )}{7}

45 x^{2} - \frac{72 x}{7} - \frac{27}{7}

Solution steps

\frac{( 21 x - 9 ) ( 15 x + 3 )}{7}

Expand

(21 x - 9) (15 x + 3) : 315 x^{2} - 72 x - 27

= \frac{315 x ^{2} - 72 x - 27}{7}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{315 x ^{2} - 72 x - 27}{7} = \frac{315 x ^{2}}{7} - \frac{72 x}{7} - \frac{27}{7}

= \frac{315 x ^{2}}{7} - \frac{72 x}{7} - \frac{27}{7}

Divide the numbers:

\frac{315}{7} = 45

= 45 x^{2} - \frac{72 x}{7} - \frac{27}{7}

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What is expand ((21x-9)(15x+3))/7 ?
The solution to expand ((21x-9)(15x+3))/7 is 45x^2-(72x)/7-27/7