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Popular >

expand (x+2)(x+1)'

Solution

expand

(x + 2) (x + 1)^{'}

Solution

x (x + 1)' + 2 (x + 1)'

Solution steps

(x + 2) (x + 1)^{'}

Apply the distributive law:

a (b + c) = ab + a c

a = (x + 1)^{'}, b = x, c = 2

= (x + 1)^{^{'}} x + (x + 1)^{^{'}} 2

= x (x + 1)^{^{'}} + 2 (x + 1)^{^{'}}

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Frequently Asked Questions (FAQ)

What is expand (x+2)(x+1)' ?
The solution to expand (x+2)(x+1)' is x(x+1)'+2(x+1)'