What is expand 2((x-1)+3=(2x-1)-16) ?

The solution to expand 2((x-1)+3=(2x-1)-16) is 2x+4=2x-33

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand 2((x-1)+3=(2x-1)-16)

expand

2 ((x - 1) + 3 = (2 x - 1) - 16)

2 x + 4 = 2 x - 33

Solution steps

2 ((x - 1) + 3 = (2 x - 1) - 16)

Distribute parentheses

2 (x - 1) + 2 \cdot 3 = (2 x - 1) + 2 (- 16)

Apply minus-plus rules

+ (- a) = - a

2 (x - 1) + 2 \cdot 3 = (2 x - 1) - 2 \cdot 16

Simplify

2 (x - 1) + 2 \cdot 3 = (2 x - 1) - 2 \cdot 16 : 2 x + 4 = 2 x - 33

2 x + 4 = 2 x - 33

\frac{d}{d t} ((x) (b + c (t - 2 s)^{2}))

\frac{( 25 - y ) ^{2}}{25}

5 (2 e + 6)

\frac{π w + s}{( 1 - π ) w - s}

\frac{x ^{2} + ( 1 + y ) ^{2}}{x y}

What is expand 2((x-1)+3=(2x-1)-16) ?
The solution to expand 2((x-1)+3=(2x-1)-16) is 2x+4=2x-33