What is expand (2n-1)/(n^2(n-1)^2) ?

The solution to expand (2n-1)/(n^2(n-1)^2) is (2n-1)/(n^4-2n^3+n^2)

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expand (2n-1)/(n^2(n-1)^2)

expand

\frac{2 n - 1}{n ^{2} ( n - 1 ) ^{2}}

\frac{2 n - 1}{n ^{4} - 2 n ^{3} + n ^{2}}

Solution steps

\frac{2 n - 1}{n ^{2} ( n - 1 ) ^{2}}

(n - 1)^{2} = n^{2} - 2 n + 1

= \frac{2 n - 1}{n ^{2} ( n ^{2} - 2 n + 1 )}

Expand

n^{2} (n^{2} - 2 n + 1) : n^{4} - 2 n^{3} + n^{2}

= \frac{2 n - 1}{n ^{4} - 2 n ^{3} + n ^{2}}

\frac{( 2 x + 3 ) ( x - 1 )}{2}

\frac{( 6 + x ^{2} + 5 x ) ^{2}}{( a + 2 )}

(3 c - 4 e) 2 (- 3 c - 4 d)

- \frac{1000}{( s - 1 ) ( s + 1 ) ( s + 20 )}

\frac{2}{s ( s ^{2} + 4 s )}

What is expand (2n-1)/(n^2(n-1)^2) ?
The solution to expand (2n-1)/(n^2(n-1)^2) is (2n-1)/(n^4-2n^3+n^2)