What is expand ((30x+1)(10x+1))/(300) ?

The solution to expand ((30x+1)(10x+1))/(300) is x^2+(2x)/(15)+1/300

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expand ((30x+1)(10x+1))/(300)

expand

\frac{( 30 x + 1 ) ( 10 x + 1 )}{300}

x^{2} + \frac{2 x}{15} + \frac{1}{300}

Solution steps

\frac{( 30 x + 1 ) ( 10 x + 1 )}{300}

Expand

(30 x + 1) (10 x + 1) : 300 x^{2} + 40 x + 1

= \frac{300 x ^{2} + 40 x + 1}{300}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{300 x ^{2} + 40 x + 1}{300} = \frac{300 x ^{2}}{300} + \frac{40 x}{300} + \frac{1}{300}

= \frac{300 x ^{2}}{300} + \frac{40 x}{300} + \frac{1}{300}

Divide the numbers:

\frac{300}{300} = 1

= x^{2} + \frac{40 x}{300} + \frac{1}{300}

Cancel

\frac{40 x}{300} : \frac{2 x}{15}

= x^{2} + \frac{2 x}{15} + \frac{1}{300}

\frac{2 ( x + h ) - 3}{( x + h + 4 )}

\frac{37}{( s + 4 ) ^{2}}

x (9 - x) d x

y (y^{2} - 2 y = x^{2} - x + c)

(u^{2} y^{2} - y^{2}) (u d y + y d u)

What is expand ((30x+1)(10x+1))/(300) ?
The solution to expand ((30x+1)(10x+1))/(300) is x^2+(2x)/(15)+1/300