What is expand (3y(4y+1))/(7(4y-1)) ?

The solution to expand (3y(4y+1))/(7(4y-1)) is (12y^2+3y)/(28y-7)

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expand (3y(4y+1))/(7(4y-1))

expand

\frac{3 y ( 4 y + 1 )}{7 ( 4 y - 1 )}

\frac{12 y ^{2} + 3 y}{28 y - 7}

Solution steps

\frac{3 y ( 4 y + 1 )}{7 ( 4 y - 1 )}

Expand

7 (4 y - 1) : 28 y - 7

= \frac{3 y ( 4 y + 1 )}{28 y - 7}

Expand

3 y (4 y + 1) : 12 y^{2} + 3 y

= \frac{12 y ^{2} + 3 y}{28 y - 7}

\frac{121 ( 3 π - 8 )}{8} + 121 π

\frac{2}{27} (3 e^{3 x} x - e^{3 x})

(84) (k)^{3} (x)^{9 - 6}

\frac{( 2 - x )}{( 1 + 2 x ) ^{2}}

4 (2 x + 7 = - 22 + 18)

What is expand (3y(4y+1))/(7(4y-1)) ?
The solution to expand (3y(4y+1))/(7(4y-1)) is (12y^2+3y)/(28y-7)