What is expand 2/27 (3e^{3x}x-e^{3x}) ?

The solution to expand 2/27 (3e^{3x}x-e^{3x}) is (2e^{3x}x)/9-2/27 e^{3x}

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expand 2/27 (3e^{3x}x-e^{3x})

expand

\frac{2}{27} (3 e^{3 x} x - e^{3 x})

\frac{2 e ^{3 x} x}{9} - \frac{2}{27} e^{3 x}

Solution steps

\frac{2}{27} (3 e^{3 x} x - e^{3 x})

Apply the distributive law:

a (b - c) = ab - a c

a = \frac{2}{27}, b = 3 e^{3 x} x, c = e^{3 x}

= \frac{2}{27} \cdot 3 e^{3 x} x - \frac{2}{27} e^{3 x}

= 3 \cdot \frac{2}{27} e^{3 x} x - \frac{2}{27} e^{3 x}

Simplify

3 \cdot \frac{2}{27} e^{3 x} x - \frac{2}{27} e^{3 x} : \frac{2 e ^{3 x} x}{9} - \frac{2}{27} e^{3 x}

= \frac{2 e ^{3 x} x}{9} - \frac{2}{27} e^{3 x}

(84) (k)^{3} (x)^{9 - 6}

\frac{( 2 - x )}{( 1 + 2 x ) ^{2}}

4 (2 x + 7 = - 22 + 18)

\frac{( 4 u + 1 ) ( 2 u - 3 )}{4}

12 + 11 \cdot 101 + 93

What is expand 2/27 (3e^{3x}x-e^{3x}) ?
The solution to expand 2/27 (3e^{3x}x-e^{3x}) is (2e^{3x}x)/9-2/27 e^{3x}