What is expand ((4u+1)(2u-3))/4 ?

The solution to expand ((4u+1)(2u-3))/4 is 2u^2-(5u)/2-3/4

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expand ((4u+1)(2u-3))/4

expand

\frac{( 4 u + 1 ) ( 2 u - 3 )}{4}

2 u^{2} - \frac{5 u}{2} - \frac{3}{4}

Solution steps

\frac{( 4 u + 1 ) ( 2 u - 3 )}{4}

Expand

(4 u + 1) (2 u - 3) : 8 u^{2} - 10 u - 3

= \frac{8 u ^{2} - 10 u - 3}{4}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{8 u ^{2} - 10 u - 3}{4} = \frac{8 u ^{2}}{4} - \frac{10 u}{4} - \frac{3}{4}

= \frac{8 u ^{2}}{4} - \frac{10 u}{4} - \frac{3}{4}

Divide the numbers:

\frac{8}{4} = 2

= 2 u^{2} - \frac{10 u}{4} - \frac{3}{4}

Cancel

\frac{10 u}{4} : \frac{5 u}{2}

= 2 u^{2} - \frac{5 u}{2} - \frac{3}{4}

12 + 11 \cdot 101 + 93

\frac{k ( 9 - k )}{2} + (6 - k)

(x + y)^{2} + 8

\frac{( - 19 - 3 y ) ^{2}}{2}

(7 x - 4) \cdot (8 x + 5)^{'}

What is expand ((4u+1)(2u-3))/4 ?
The solution to expand ((4u+1)(2u-3))/4 is 2u^2-(5u)/2-3/4