What is expand (2x+3)/((x-4)(x-3)) ?

The solution to expand (2x+3)/((x-4)(x-3)) is (2x+3)/(x^2-7x+12)

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expand (2x+3)/((x-4)(x-3))

expand

\frac{2 x + 3}{( x - 4 ) ( x - 3 )}

\frac{2 x + 3}{x ^{2} - 7 x + 12}

Solution steps

\frac{2 x + 3}{( x - 4 ) ( x - 3 )}

Expand

(x - 4) (x - 3) : x^{2} - 7 x + 12

= \frac{2 x + 3}{x ^{2} - 7 x + 12}

\frac{x ^{2}}{( x - 1 ) ^{4}}

x^{\circ - 1} (x + 2)

- \frac{( 10 - x ) ^{4}}{25}

\frac{d}{d y} ((x) (y - p (x) x))

(2 + \frac{y}{x ^{2}}) d y

What is expand (2x+3)/((x-4)(x-3)) ?
The solution to expand (2x+3)/((x-4)(x-3)) is (2x+3)/(x^2-7x+12)