What is expand (3x-9)(2x+1)' ?

The solution to expand (3x-9)(2x+1)' is 3x(2x+1)'-9(2x+1)'

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expand (3x-9)(2x+1)'

expand

(3 x - 9) (2 x + 1)^{'}

3 x (2 x + 1)' - 9 (2 x + 1)'

Solution steps

(3 x - 9) (2 x + 1)^{'}

Apply the distributive law:

a (b - c) = ab - a c

a = (2 x + 1)^{'}, b = 3 x, c = 9

= (2 x + 1)^{^{'}} 3 x - (2 x + 1)^{^{'}} 9

= 3 x (2 x + 1)^{^{'}} - 9 (2 x + 1)^{^{'}}

2 (x + 10) (e^{x} + e^{- x})

\frac{e ^{x}}{( e ^{x} + 1 ) ^{3}}

(32 x^{2} - 35 x = 49) (4 x - 8)

- 4 ln (x - 2) + 3 (1 - x)

\frac{3 ( x + 3 ) ( x + 5 )}{x ^{6}}

What is expand (3x-9)(2x+1)' ?
The solution to expand (3x-9)(2x+1)' is 3x(2x+1)'-9(2x+1)'