What is expand (32x^2-35x=49)(4x-8) ?

The solution to expand (32x^2-35x=49)(4x-8) is 128x^3-256x^2-35x=392

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expand (32x^2-35x=49)(4x-8)

expand

(32 x^{2} - 35 x = 49) (4 x - 8)

128 x^{3} - 256 x^{2} - 35 x = 392

Solution steps

(32 x^{2} - 35 x = 49) (4 x - 8)

= (32 x^{2} - 35 \cdot 49 = x) (4 x - 8)

Apply FOIL method:

(a + b) (c + d) = a c + a d + b c + b d

a = 32 x^{2}, b = - 35 x = 49, c = 4 x, d = - 8

= 32 x^{2} \cdot 4 x + 32 x^{2} (- 8) + (- 35 x = 49) \cdot 4 x + (- 35 x = 49) (- 8)

Apply minus-plus rules

+ (- a) = - a, (- a) (- b) = ab

32 \cdot 4 x^{2} x - 32 \cdot 8 x^{2} - 35 x = 49 \cdot 4 x + 35 x = 49 \cdot 8

Simplify

32 \cdot 4 x^{2} x - 32 \cdot 8 x^{2} - 35 x = 49 \cdot 4 x + 35 x = 49 \cdot 8 : 128 x^{3} - 256 x^{2} - 35 x = 392

128 x^{3} - 256 x^{2} - 35 x = 392

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What is expand (32x^2-35x=49)(4x-8) ?
The solution to expand (32x^2-35x=49)(4x-8) is 128x^3-256x^2-35x=392