What is expand 4/((s+1)(s+3)s) ?

The solution to expand 4/((s+1)(s+3)s) is 4/(s^3+4s^2+3s)

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expand 4/((s+1)(s+3)s)

expand

\frac{4}{( s + 1 ) ( s + 3 ) s}

\frac{4}{s ^{3} + 4 s ^{2} + 3 s}

Solution steps

\frac{4}{( s + 1 ) ( s + 3 ) s}

Expand

(s + 1) (s + 3) s : s^{3} + 4 s^{2} + 3 s

= \frac{4}{s ^{3} + 4 s ^{2} + 3 s}

A (- 2, 2) y B (3, - 4)

\frac{f ( 14 + h ) - 14}{h}

e^{t} (- e^{- t} t - e^{- t} + C)

(4, - 10) y (7, r)

, (p + 3) (p - 2)

What is expand 4/((s+1)(s+3)s) ?
The solution to expand 4/((s+1)(s+3)s) is 4/(s^3+4s^2+3s)