What is expand (3n+5)/(n(n-1)(n-2)) ?

The solution to expand (3n+5)/(n(n-1)(n-2)) is (3n+5)/(n^3-3n^2+2n)

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expand (3n+5)/(n(n-1)(n-2))

expand

\frac{3 n + 5}{n ( n - 1 ) ( n - 2 )}

\frac{3 n + 5}{n ^{3} - 3 n ^{2} + 2 n}

Solution steps

\frac{3 n + 5}{n ( n - 1 ) ( n - 2 )}

Expand

n (n - 1) (n - 2) : n^{3} - 3 n^{2} + 2 n

= \frac{3 n + 5}{n ^{3} - 3 n ^{2} + 2 n}

\frac{( x + 1 ) ^{2}}{( x - 1 ) ( x - 3 )}

(2 x^{2} + 3 x - 3) e^{x}

\frac{40}{( z ^{2} + 16 ) z ^{2}}

\frac{1 - 3 x ^{2}}{( 1 - x ^{2} ) ^{2}}

\frac{2 ( 4 a + 4 )}{a + 9}

What is expand (3n+5)/(n(n-1)(n-2)) ?
The solution to expand (3n+5)/(n(n-1)(n-2)) is (3n+5)/(n^3-3n^2+2n)