What is e^{i(2t+pi/4)} ?

The solution to e^{i(2t+pi/4)} is cos((8t+pi)/4)+isin((8t+pi)/4)

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simplify e^{i(2t+pi/4)}

simplify

e^{i (2 t + \frac{π}{4})}

cos (\frac{8 t + π}{4}) + i sin (\frac{8 t + π}{4})

Solution steps

e^{i (2 t + \frac{π}{4})}

Apply imaginary number rule:

e^{ia} = cos (a) + i sin (a)

= cos (\frac{8 t + π}{4}) + i sin (\frac{8 t + π}{4})

\frac{7 ( x - 1 )}{( x + 1 ) ( x - 2 )}

\frac{2 ( X - 8 )}{5}

arcsin (\frac{1}{2} (x + 1)) + c

(2 x - 1) (e^{x} x - e^{x} + 2)

y (15 y + 31 = 61)

What is e^{i(2t+pi/4)} ?
The solution to e^{i(2t+pi/4)} is cos((8t+pi)/4)+isin((8t+pi)/4)