What are the solutions to the equation 5x^2-5x-3=0 ?

The solutions to the equation 5x^2-5x-3=0 are x=(5+sqrt(85))/(10),x=(5-sqrt(85))/(10)

Find the zeros of 5x^2-5x-3=0

The zeros of 5x^2-5x-3=0 are x=(5+sqrt(85))/(10),x=(5-sqrt(85))/(10)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 x^{2} - 5 x - 3 = 0

x = \frac{5 + 85}{10}, x = \frac{5 - 85}{10}

Decimal Notation

x = 1.42195 \dots, x = - 0.42195 \dots

Solution steps

5 x^{2} - 5 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 5 ( - 3 )}{2 \cdot 5}

(- 5)^{2} - 4 \cdot 5 (- 3) = 85

x_{1, 2} = \frac{- ( - 5 ) \pm 85}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 85}{2 \cdot 5}, x_{2} = \frac{- ( - 5 ) - 85}{2 \cdot 5}

x = \frac{- ( - 5 ) + 85}{2 \cdot 5} : \frac{5 + 85}{10}

x = \frac{- ( - 5 ) - 85}{2 \cdot 5} : \frac{5 - 85}{10}

The solutions to the quadratic equation are:

x = \frac{5 + 85}{10}, x = \frac{5 - 85}{10}

lo g_{25} (\frac{1}{125})

x^{3} + 7 x^{2} - x - 7 \geq 0

(\frac{x ^{3}}{x ^{2}})^{- 1}

- 5 < 6 x + 1 < 25

n + 1 \leq - 3 or - 4 n < - 8

What are the solutions to the equation 5x^2-5x-3=0 ?
The solutions to the equation 5x^2-5x-3=0 are x=(5+sqrt(85))/(10),x=(5-sqrt(85))/(10)
Find the zeros of 5x^2-5x-3=0
The zeros of 5x^2-5x-3=0 are x=(5+sqrt(85))/(10),x=(5-sqrt(85))/(10)