What is the d/(dt)((x)(x-2)^2) ?

The d/(dt)((x)(x-2)^2) is 3t^2-8t+4

What is the first d/(dt)((x)(x-2)^2) ?

The first d/(dt)((x)(x-2)^2) is 3t^2-8t+4

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\frac{d}{d t} ((t) (t - 2)^{2})

3 t^{2} - 8 t + 4

Solution steps

\frac{d}{d t} ((t) (t - 2)^{2})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = t, g = (t - 2)^{2}

= \frac{d t}{d t} (t - 2)^{2} + \frac{d}{d t} ((t - 2)^{2}) t

\frac{d t}{d t} = 1

\frac{d}{d t} ((t - 2)^{2}) = 2 (t - 2)

= 1 \cdot (t - 2)^{2} + 2 (t - 2) t

Simplify

1 \cdot (t - 2)^{2} + 2 (t - 2) t : 3 t^{2} - 8 t + 4

= 3 t^{2} - 8 t + 4

\frac{6}{( 2 t + 7 ) ^{4}}

\frac{x ^{2} + 1}{x ^{2}}

- \frac{1}{3} \cdot 6 x

(1 - x y) d y

\frac{d}{d y} ((x) (x y + e^{x y}))

What is the d/(dt)((x)(x-2)^2) ?
The d/(dt)((x)(x-2)^2) is 3t^2-8t+4
What is the first d/(dt)((x)(x-2)^2) ?
The first d/(dt)((x)(x-2)^2) is 3t^2-8t+4