What is expand 2xy^3i^+(1+3x^2y^2)j ?

The solution to expand 2xy^3i^+(1+3x^2y^2)j is 2i^{}jxy^3+6i^{}jx^3y^5

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expand 2xy^3i^+(1+3x^2y^2)j

expand

2 x y^{3} i^{+} (1 + 3 x^{2} y^{2}) j

2 i j x y^{3} + 6 i j x^{3} y^{5}

Solution steps

2 x y^{3} i^{+} (1 + 3 x^{2} y^{2}) j

= 2 i^{+} j x y^{3} (1 + 3 x^{2} y^{2})

Apply the distributive law:

a (b + c) = ab + a c

a = 2 x y^{3} i^{+} j, b = 1, c = 3 x^{2} y^{2}

= 2 x y^{3} i^{+} j \cdot 1 + 2 x y^{3} i^{+} j \cdot 3 x^{2} y^{2}

= 2 \cdot 1 \cdot i^{+} j x y^{3} + 2 \cdot 3 i^{+} j x^{2} x y^{3} y^{2}

Simplify

2 \cdot 1 \cdot i^{+} j x y^{3} + 2 \cdot 3 i^{+} j x^{2} x y^{3} y^{2} : 2 i j x y^{3} + 6 i j x^{3} y^{5}

= 2 i j x y^{3} + 6 i j x^{3} y^{5}

- \frac{4}{9} (2 z - 3 = 1)

a (- 1, - 1) b (- 1, 2) c (3, - 1)

\frac{( 2 x - 5 ) ( x + 3 )}{x - 2}

(x^{2} + 4 x + 3 \circ x + 1) (3)

\frac{35}{3 ( 3 j + 7 )}

What is expand 2xy^3i^+(1+3x^2y^2)j ?
The solution to expand 2xy^3i^+(1+3x^2y^2)j is 2i^{}jxy^3+6i^{}jx^3y^5