What are the solutions to the equation 5a^2+a-48=0 ?

The solutions to the equation 5a^2+a-48=0 are a=3,a=-16/5

Find the zeros of 5a^2+a-48=0

The zeros of 5a^2+a-48=0 are a=3,a=-16/5

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5 a^{2} + a - 48 = 0

a = 3, a = - \frac{16}{5}

Decimal Notation

a = 3, a = - 3.2

Solution steps

5 a^{2} + a - 48 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 5 ( - 48 )}{2 \cdot 5}

1^{2} - 4 \cdot 5 (- 48) = 31

a_{1, 2} = \frac{- 1 \pm 31}{2 \cdot 5}

Separate the solutions

a_{1} = \frac{- 1 + 31}{2 \cdot 5}, a_{2} = \frac{- 1 - 31}{2 \cdot 5}

a = \frac{- 1 + 31}{2 \cdot 5} : 3

a = \frac{- 1 - 31}{2 \cdot 5} : - \frac{16}{5}

The solutions to the quadratic equation are:

a = 3, a = - \frac{16}{5}

1922

2^{- \frac{3}{2}}

3 m^{2} - 5 m - 28 = 0

44 x^{5} - 40 x^{4} - 4 x^{3}

(5 - 3) (5 + 3)

What are the solutions to the equation 5a^2+a-48=0 ?
The solutions to the equation 5a^2+a-48=0 are a=3,a=-16/5
Find the zeros of 5a^2+a-48=0
The zeros of 5a^2+a-48=0 are a=3,a=-16/5