What are the solutions to the equation (x+4)(5x+9)-x^2+16=0 ?

The solutions to the equation (x+4)(5x+9)-x^2+16=0 are x=-13/4 ,x=-4

Find the zeros of (x+4)(5x+9)-x^2+16=0

The zeros of (x+4)(5x+9)-x^2+16=0 are x=-13/4 ,x=-4

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(x + 4) (5 x + 9) - x^{2} + 16 = 0

x = - \frac{13}{4}, x = - 4

Solution steps

(x + 4) (5 x + 9) - x^{2} + 16 = 0

Expand

(x + 4) (5 x + 9) - x^{2} + 16 : 4 x^{2} + 29 x + 52

4 x^{2} + 29 x + 52 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 29 \pm 2 9 ^{2} - 4 \cdot 4 \cdot 52}{2 \cdot 4}

2 9^{2} - 4 \cdot 4 \cdot 52 = 3

x_{1, 2} = \frac{- 29 \pm 3}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 29 + 3}{2 \cdot 4}, x_{2} = \frac{- 29 - 3}{2 \cdot 4}

x = \frac{- 29 + 3}{2 \cdot 4} : - \frac{13}{4}

x = \frac{- 29 - 3}{2 \cdot 4} : - 4

The solutions to the quadratic equation are:

x = - \frac{13}{4}, x = - 4

- 52 a^{2} + 5119 a - 54421 = 40000

lo g_{81} (27)

z - 4.1 > - 8.6 + 2 z

0 + 2

- x^{2} + 3 x + 18 = 0

What are the solutions to the equation (x+4)(5x+9)-x^2+16=0 ?
The solutions to the equation (x+4)(5x+9)-x^2+16=0 are x=-13/4 ,x=-4
Find the zeros of (x+4)(5x+9)-x^2+16=0
The zeros of (x+4)(5x+9)-x^2+16=0 are x=-13/4 ,x=-4