What is expand (x^3(3ln(x)-1))/9 ?

The solution to expand (x^3(3ln(x)-1))/9 is (x^3ln(x))/3-(x^3)/9

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expand (x^3(3ln(x)-1))/9

expand

\frac{x ^{3} ( 3 ln ( x ) - 1 )}{9}

\frac{x ^{3} ln ( x )}{3} - \frac{x ^{3}}{9}

Solution steps

\frac{x ^{3} ( 3 ln ( x ) - 1 )}{9}

Expand

x^{3} (3 ln (x) - 1) : 3 x^{3} ln (x) - x^{3}

= \frac{3 x ^{3} ln ( x ) - x ^{3}}{9}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{3 x ^{3} ln ( x ) - x ^{3}}{9} = \frac{3 x ^{3} ln ( x )}{9} - \frac{x ^{3}}{9}

= \frac{3 x ^{3} ln ( x )}{9} - \frac{x ^{3}}{9}

Cancel

\frac{3 x ^{3} ln ( x )}{9} : \frac{x ^{3} ln ( x )}{3}

= \frac{x ^{3} ln ( x )}{3} - \frac{x ^{3}}{9}

- \frac{3 ( b ^{2} + b + 6 )}{2}

\frac{5 ( - x + 4 )}{x ^{3}}

(\frac{- 20 - 2 y}{7})^{2}

\frac{2 s ^{2} + 6 s + 5}{( s + 2 ) ( s + 1 )}

x (e^{2 x} + x^{4})

What is expand (x^3(3ln(x)-1))/9 ?
The solution to expand (x^3(3ln(x)-1))/9 is (x^3ln(x))/3-(x^3)/9