What is expand (-1)/3 (2y-9=-2) ?

The solution to expand (-1)/3 (2y-9=-2) is -(2y)/3+3= 2/3

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expand (-1)/3 (2y-9=-2)

expand

\frac{- 1}{3} (2 y - 9 = - 2)

- \frac{2 y}{3} + 3 = \frac{2}{3}

Solution steps

\frac{- 1}{3} (2 y - 9 = - 2)

Distribute parentheses

= \frac{- 1}{3} \cdot 2 y + \frac{- 1}{3} (- 9 =) + \frac{- 1}{3} (- 2)

Apply minus-plus rules

+ (- a) = - a

2 \cdot \frac{- 1}{3} y - 9 \cdot \frac{- 1}{3} = - 2 \cdot \frac{- 1}{3}

Simplify

2 \cdot \frac{- 1}{3} y - 9 \cdot \frac{- 1}{3} = - 2 \cdot \frac{- 1}{3} : - \frac{2 y}{3} + 3 = \frac{2}{3}

- \frac{2 y}{3} + 3 = \frac{2}{3}

(1 + y + y^{2}) d x + x (x^{2} - 4) d y

\frac{( 9 a + 1 ) ^{3}}{27}

\frac{9}{( x - 2 ) ^{2}}

(x + h) e

\frac{( 4 x ^{2} + y ) ^{2}}{x ^{2} + y}

What is expand (-1)/3 (2y-9=-2) ?
The solution to expand (-1)/3 (2y-9=-2) is -(2y)/3+3= 2/3