What is expand-(-2x^2+3x-7=0) ?

The solution to expand-(-2x^2+3x-7=0) is 2x^2-3x+7=0

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expand-(-2x^2+3x-7=0)

expand

- (- 2 x^{2} + 3 x - 7 = 0)

2 x^{2} - 3 x + 7 = 0

Solution steps

- (- 2 x^{2} + 3 x - 7 = 0)

= - (- 2 x^{2} + 3 x - 7 \cdot 0 =)

Distribute parentheses

= - (- 2 x^{2}) - (3 x) - (- 7 = 0)

Apply minus-plus rules

- (- a) = a, - (a) = - a

2 x^{2} - 3 x + 7 = 0

14 a + 18 a

3 t^{2} - 5 t + 6 + 8 t^{2} + 7 t - 9

\frac{1}{( x ^{2} - 1 ) ( x + 2 ) ( 2 x + 1 )}

\frac{( x + 3 ) ( x + 1 )}{x ^{2} + 2 x + 3}

What is expand-(-2x^2+3x-7=0) ?
The solution to expand-(-2x^2+3x-7=0) is 2x^2-3x+7=0