What is expand 2(4Y(A)+2+Y(A)A=1) ?

The solution to expand 2(4Y(A)+2+Y(A)A=1) is 8Y(A)+4+2AY(A)=1

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expand 2(4Y(A)+2+Y(A)A=1)

expand

2 (4 Y (A) + 2 + Y (A) A = 1)

8 Y (A) + 4 + 2 A Y (A) = 1

Solution steps

2 (4 Y (A) + 2 + Y (A) A = 1)

= 2 (4 Y (A) + 2 + 1 = A Y (A))

Distribute parentheses

2 \cdot 4 Y (A) + 2 \cdot 2 + 2 Y (A) A = 1

2 \cdot 4 Y (A) + 2 \cdot 2 + 2 A Y (A) = 1

Expand

2 \cdot 4 Y (A) + 2 \cdot 2 + 2 A Y (A) : 8 Y (A) + 4 + 2 A Y (A)

8 Y (A) + 4 + 2 A Y (A) = 1

x^{3} y \cdot I n (x y + 1) d x

(e^{2} + 2) (e^{2} - 2)

\frac{( x - 1 ) ^{2}}{x ^{2} - 2 x}

x^{3} y \cdot I n (x y + 1) d y

\frac{( x + 6 )}{2 ( x - 6 )}

What is expand 2(4Y(A)+2+Y(A)A=1) ?
The solution to expand 2(4Y(A)+2+Y(A)A=1) is 8Y(A)+4+2AY(A)=1