What is expand (x^3-12x-16)/((x-1)^2) ?

The solution to expand (x^3-12x-16)/((x-1)^2) is (x^3-12x-16)/(x^2-2x+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (x^3-12x-16)/((x-1)^2)

expand

\frac{x ^{3} - 12 x - 16}{( x - 1 ) ^{2}}

\frac{x ^{3} - 12 x - 16}{x ^{2} - 2 x + 1}

Solution steps

\frac{x ^{3} - 12 x - 16}{( x - 1 ) ^{2}}

(x - 1)^{2} = x^{2} - 2 x + 1

= \frac{x ^{3} - 12 x - 16}{x ^{2} - 2 x + 1}

2 (x + y) (d x + d y)

(e^{t} + e^{- t}) e^{t} + e^{- t}

- \frac{5 ( 5 - 1 )}{2}

\frac{6 ( y - 9 )}{55}

\frac{2 s + 3}{( s + 2 ) ( s - 3 ) ( s + 1 )}

What is expand (x^3-12x-16)/((x-1)^2) ?
The solution to expand (x^3-12x-16)/((x-1)^2) is (x^3-12x-16)/(x^2-2x+1)