What is expand df(u^2+ln(v)-w^2) ?

The solution to expand df(u^2+ln(v)-w^2) is u^2df+ln(v)df-w^2df

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expand df(u^2+ln(v)-w^2)

expand

df (u^{2} + ln (v) - w^{2})

u^{2} df + ln (v) df - w^{2} df

Solution steps

df (u^{2} + ln (v) - w^{2})

Distribute parentheses

= df u^{2} + df ln (v) + df (- w^{2})

Apply minus-plus rules

+ (- a) = - a

= u^{2} df + ln (v) df - w^{2} df

(2 - t) (H (t - 1) - H (t - 2))

(a + b t)^{2} d t

\frac{x ^{2} ( x + 3 ) ^{2}}{x - 3}

(x e^{- x} + x) (x e^{- x} - x)

- e^{- r t} (x + u)^{0.5} + p (x - u)

What is expand df(u^2+ln(v)-w^2) ?
The solution to expand df(u^2+ln(v)-w^2) is u^2df+ln(v)df-w^2df