What is expand e(e^{(x-1)}-x^{(e-1)}) ?

The solution to expand e(e^{(x-1)}-x^{(e-1)}) is e^x-ex^{e-1}

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expand e(e^{(x-1)}-x^{(e-1)})

expand

e (e^{(x - 1)} - x^{(e - 1)})

e^{x} - e x^{e - 1}

Solution steps

e (e^{(x - 1)} - x^{(e - 1)})

Apply the distributive law:

a (b - c) = ab - a c

a = e, b = e^{(x - 1)}, c = x^{(e - 1)}

= e e^{(x - 1)} - e x^{(e - 1)}

e e^{x - 1} = e^{x}

= e^{x} - e x^{e - 1}

(x^{2} + 1) \circ (x + 1) (x)

- (9 x^{3} + 9 x^{2} + 6 x + 2) e - 3 x^{27}

\frac{5 x ^{2}}{( x - 4 ) ( x ^{2} - 9 )}

8 (e^{x} + 2)^{2}

π (5 - x^{2})^{2}

What is expand e(e^{(x-1)}-x^{(e-1)}) ?
The solution to expand e(e^{(x-1)}-x^{(e-1)}) is e^x-ex^{e-1}