What is expand 4(2x^2-x-1)^2 ?

The solution to expand 4(2x^2-x-1)^2 is 16x^4-16x^3-12x^2+8x+4

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expand 4(2x^2-x-1)^2

expand

4 (2 x^{2} - x - 1)^{2}

16 x^{4} - 16 x^{3} - 12 x^{2} + 8 x + 4

Solution steps

4 (2 x^{2} - x - 1)^{2}

(2 x^{2} - x - 1)^{2} = 4 x^{4} - 4 x^{3} - 3 x^{2} + 2 x + 1

= 4 (4 x^{4} - 4 x^{3} - 3 x^{2} + 2 x + 1)

Distribute parentheses

= 4 \cdot 4 x^{4} + 4 (- 4 x^{3}) + 4 (- 3 x^{2}) + 4 \cdot 2 x + 4 \cdot 1

Apply minus-plus rules

+ (- a) = - a

= 4 \cdot 4 x^{4} - 4 \cdot 4 x^{3} - 4 \cdot 3 x^{2} + 4 \cdot 2 x + 4 \cdot 1

Simplify

4 \cdot 4 x^{4} - 4 \cdot 4 x^{3} - 4 \cdot 3 x^{2} + 4 \cdot 2 x + 4 \cdot 1 : 16 x^{4} - 16 x^{3} - 12 x^{2} + 8 x + 4

= 16 x^{4} - 16 x^{3} - 12 x^{2} + 8 x + 4

\frac{d}{d k} ((e) (e - m k^{2}))

\frac{4 ( a + h ) - 1}{5 ( a + h ) + 4}

(x - 2) (8 - x) \circ (1 - 2 t)

4 (0.4 y = 0.3 x + 1.2)

\frac{2}{x} \frac{2}{x}

What is expand 4(2x^2-x-1)^2 ?
The solution to expand 4(2x^2-x-1)^2 is 16x^4-16x^3-12x^2+8x+4