What is expand (3-5a-5h+4(a+h)^2)/h ?

The solution to expand (3-5a-5h+4(a+h)^2)/h is 3/h-(5a)/h-5+(4a^2)/h+8a+4h

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expand (3-5a-5h+4(a+h)^2)/h

expand

\frac{3 - 5 a - 5 h + 4 ( a + h ) ^{2}}{h}

\frac{3}{h} - \frac{5 a}{h} - 5 + \frac{4 a ^{2}}{h} + 8 a + 4 h

Solution steps

\frac{3 - 5 a - 5 h + 4 ( a + h ) ^{2}}{h}

(a + h)^{2} = a^{2} + 2 ah + h^{2}

= \frac{3 - 5 a - 5 h + 4 ( h ^{2} + 2 ah + a ^{2} )}{h}

Expand

3 - 5 a - 5 h + 4 (a^{2} + 2 ah + h^{2}) : 3 - 5 a - 5 h + 4 a^{2} + 8 ah + 4 h^{2}

= \frac{3 - 5 a - 5 h + 4 a ^{2} + 8 ah + 4 h ^{2}}{h}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{3 - 5 a - 5 h + 4 a ^{2} + 8 ah + 4 h ^{2}}{h} = \frac{3}{h} - \frac{5 a}{h} - \frac{5 h}{h} + \frac{4 a ^{2}}{h} + \frac{8 ah}{h} + \frac{4 h ^{2}}{h}

= \frac{3}{h} - \frac{5 a}{h} - \frac{5 h}{h} + \frac{4 a ^{2}}{h} + \frac{8 ah}{h} + \frac{4 h ^{2}}{h}

Cancel

\frac{5 h}{h} : 5

= \frac{3}{h} - \frac{5 a}{h} - 5 + \frac{4 a ^{2}}{h} + \frac{8 ah}{h} + \frac{4 h ^{2}}{h}

Cancel

\frac{8 ah}{h} : 8 a

= \frac{3}{h} - \frac{5 a}{h} - 5 + \frac{4 a ^{2}}{h} + 8 a + \frac{4 h ^{2}}{h}

Cancel

\frac{4 h ^{2}}{h} : 4 h

= \frac{3}{h} - \frac{5 a}{h} - 5 + \frac{4 a ^{2}}{h} + 8 a + 4 h

5 + 4 (2 x - 1 = 17)

- sin (2 π f (x - a))

∣ f (x - 5) - 10 ∣

(8 x^{2} - 6 x - 3) - (9 x^{2} + 7 x = 5)

A (- 2, - 3) B (6, 9)

What is expand (3-5a-5h+4(a+h)^2)/h ?
The solution to expand (3-5a-5h+4(a+h)^2)/h is 3/h-(5a)/h-5+(4a^2)/h+8a+4h