What is expand (8x^2-6x-3)-(9x^2+7x=5) ?

The solution to expand (8x^2-6x-3)-(9x^2+7x=5) is -x^2-13x-3=5

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expand (8x^2-6x-3)-(9x^2+7x=5)

expand

(8 x^{2} - 6 x - 3) - (9 x^{2} + 7 x = 5)

- x^{2} - 13 x - 3 = 5

Solution steps

(8 x^{2} - 6 x - 3) - (9 x^{2} + 7 x = 5)

= (8 x^{2} - 6 x - 3) - (9 x^{2} + 7 \cdot 5 = x)

- (9 x^{2} + 7 x = 5) : - 9 x^{2} - 7 x = 5

(8 x^{2} - 6 x - 3) - 9 x^{2} - 7 x = 5

Expand

(8 x^{2} - 6 x - 3) - 9 x^{2} - 7 x : - x^{2} - 13 x - 3

- x^{2} - 13 x - 3 = 5

A (- 2, - 3) B (6, 9)

(- 2, - 1, 2) x (2, 2, 2)

(x_{+ 1})^{2}

(sin (θ) - e^{- i x} cos (θ))^{2}

(x (x^{2} + 1)^{3}) d x

What is expand (8x^2-6x-3)-(9x^2+7x=5) ?
The solution to expand (8x^2-6x-3)-(9x^2+7x=5) is -x^2-13x-3=5