What is (sin(θ)-e^{-ix}cos(θ))^2 ?

The solution to (sin(θ)-e^{-ix}cos(θ))^2 is (sin(θ)-cos(θ)(cos(x)-isin(x)))^2

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simplify (sin(θ)-e^{-ix}cos(θ))^2

simplify

(sin (θ) - e^{- i x} cos (θ))^{2}

(sin (θ) - cos (θ) (cos (x) - i sin (x)))^{2}

Solution steps

(sin (θ) - e^{- i x} cos (θ))^{2}

e^{- i x} = cos (x) - i sin (x)

= (sin (θ) - cos (θ) (cos (x) - i sin (x)))^{2}

(x (x^{2} + 1)^{3}) d x

y (2 x - y e^{y})

\frac{( x - 6 ) ^{2}}{( 2 - 3 x )}

- 2 [x (x + 3) (x - 1) (x - 4)]

(e^{x} - 1) e^{x}

What is (sin(θ)-e^{-ix}cos(θ))^2 ?
The solution to (sin(θ)-e^{-ix}cos(θ))^2 is (sin(θ)-cos(θ)(cos(x)-isin(x)))^2