What are the solutions to the equation 16x^2-24x-27=0 ?

The solutions to the equation 16x^2-24x-27=0 are x= 9/4 ,x=-3/4

Find the zeros of 16x^2-24x-27=0

The zeros of 16x^2-24x-27=0 are x= 9/4 ,x=-3/4

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16 x^{2} - 24 x - 27 = 0

x = \frac{9}{4}, x = - \frac{3}{4}

Decimal Notation

x = 2.25, x = - 0.75

Solution steps

16 x^{2} - 24 x - 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 16 ( - 27 )}{2 \cdot 16}

(- 24)^{2} - 4 \cdot 16 (- 27) = 48

x_{1, 2} = \frac{- ( - 24 ) \pm 48}{2 \cdot 16}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 48}{2 \cdot 16}, x_{2} = \frac{- ( - 24 ) - 48}{2 \cdot 16}

x = \frac{- ( - 24 ) + 48}{2 \cdot 16} : \frac{9}{4}

x = \frac{- ( - 24 ) - 48}{2 \cdot 16} : - \frac{3}{4}

The solutions to the quadratic equation are:

x = \frac{9}{4}, x = - \frac{3}{4}

\frac{7}{8}

x^{2} = - 15 x

\frac{7 ^{- 2}}{2 ^{- 3}}

- 12 x^{2} + 5 x + 7 \leq 5

r - 11 = 5

What are the solutions to the equation 16x^2-24x-27=0 ?
The solutions to the equation 16x^2-24x-27=0 are x= 9/4 ,x=-3/4
Find the zeros of 16x^2-24x-27=0
The zeros of 16x^2-24x-27=0 are x= 9/4 ,x=-3/4